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Standard X

Chemistry

Relationship between Vapor Density & Relative Molecular Mass

During therma...

Question

During thermal dissociation of a gas, the vapour density:

Remains the same

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Increases

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Decreases

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Increases in some cases and decreases in others

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Solution

The correct option is B Decreases
During thermal dissociation of a gas, the vapour density decreases as the molecular weight also decreases.
Molecular weight $= 2 \times$ vapour density.
For example, consider the dissociation $N_{2} O_{4} ⇌ 2 N O_{2}$
The molecular weight of $N O_{2}$ is one half the molecular weight of $N_{2} O_{4}$ .
So, the vapour density of $N O_{2}$ is also one half the vapour density of $N_{2} O_{4}$ .

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Similar questions

Q. The vapour density of a gaseous mixture containing only

A r

and

N_{2} O_{4}

gases is

40

. When the mixture is left for some time, the vapour density is decreased and finally becomes

(37.5)

. It happened due to the dissociation of some

N_{2} O_{4}

into

N O_{2}

(A r = 40)

. What is the degree of dissociation of

N_{2} O_{4} ?

Q. The vapour density of undecomposed

N_{2} O_{4}

46

. When heated, vapour density decreases to

24.5

due to its dissociation to

{N O}_{2}

. The % dissociation of

N_{2} O_{4}

is:

The vapour density of $N_{2} O_{4}$ is $46$ . When heated vapour density decreases to $24.5$ due to its dissociation to $N O_{2}$ . The percentage dissociation of $N_{2} O_{4}$ at the final temperature is:

Q. The vapour density of undecomposed

N_{2} O_{4}

is 46. When heated, vapour density decreases to

24.5

due to its dissociation to

{N O}_{2}

. The percentage dissociation of

N_{2} O_{4}

at the final temperature is:

Q. Vapour density of the equilibrium mixture of the reaction

2 {N H}_{3} (g) ⇌ N_{2} (g) + 3 H_{2} (g)

6.0

Percent dissociation of ammonia gas is:

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