dxx2 +2x +2equals(A) x tan x +1)+ C(C) tanx+C(B) tan (1) C(D)tan x +C
The given integral is,
∫ 1 x 2 + 2 x + 2 d x
Substitute the value of x 2 + 2 x + 2 as ( x 2 + 2 x + 1 ) + 1 in the above expression.
∫ 1 x 2 + 2 x + 2 d x = ∫ 1 ( x 2 + 2 x + 1 ) + 1 d x = ∫ 1 ( x + 1 ) 2 + ( 1 ) 2 d x = tan − 1 ( x + 1 ) + C
The correct option is (B).
The given integral is,
Substitute the value of
The correct option is (B).
