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Question

dydx+2y=e3x

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Solution

We have,dydx+2y=e3x .....(1)Clearly, it is a linear differential equation of the form dydx+Py=QwhereP=2Q=e3x I.F.=eP dx =e2 dx = e2xMultiplying both sides of (1) by e2x, we gete2x dydx+2y=e2xe3xe2xdydx+2e2xy=e5xIntegrating both sides with respect to x, we gety e2x=e5xdx+Cy e2x=e5x5+Cy=15e3x+Ce-2xHence, y=15e3x+Ce-2x is the required solution.

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