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Question

dydx=x2 ex

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Solution

We have,dydx=x2exdy=x2ex dxIntegrating both sides, we getdy=x2IexII dxdy=x2ex dx-ddxx2ex dxdxy=x2ex-2xex dxy=x2ex-2xI exII dxy=x2ex-2xex dx+2ddxxex dxdxy=x2ex-2xex+2ex+Cy=x2 -2x+2ex+C

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