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Question

dydx=x5+x2-2x, x0

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Solution

We have, dydx=x5+x2-2xdy=x5+x2-2xdxIntegrating both sides, we getdy=x5+x2-2xdxy=x66+x33-2logx+CClearly, y=x66+x33-2logx+C is defined for all xR except x=0.Hence, y=x66+x33-2logx+C, where xR-0, is the solution to the given differential equation.

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