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Question


E0Cu2+|Cu=+034 V

E0Zn2+|Zn=−0.76 V

Identify the incorrect statement from the below for the above cell :
(JEE MAIN 2019)

A
If Eext=1.1 V, no flow of e or current occurs
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B
If Eext>1.1 V , Zn dissolves at Zn electrode and Cu deposits at Cu electrode
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C
If Eext<1.1 V , Zn dissolves at anode and Cu deposits at cathode
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D
If Eext>1.1 V , e flow from Cu top Zn
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Solution

The correct option is B If Eext>1.1 V , Zn dissolves at Zn electrode and Cu deposits at Cu electrode
E0cell=E0Cu2+|CuE0Zn2+|Zn=1.1 V so If Eext=1.1 V, no electron will flow At Eext>1.1 V, cell act as electrolytic cell and electron will flow from Cu to Zn . At Eext<1.1 V, cell act as electrochemical cell so Zn dissolve and Cu deposit .

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