The correct option is B If Eext>1.1 V , Zn dissolves at Zn electrode and Cu deposits at Cu electrode
E0cell=E0Cu2+|Cu−E0Zn2+|Zn=1.1 V so If Eext=1.1 V, no electron will flow At Eext>1.1 V, cell act as electrolytic cell and electron will flow from Cu to Zn . At Eext<1.1 V, cell act as electrochemical cell so Zn dissolve and Cu deposit .