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Nernst Equation

E0Zn2+/Zn=-0....

Question

$E^{0} Z n^{2 +} / Z n = - 0.76 V$ The EMF of the cell
$Z n / Z n^{2 +} (1 M) | | H C l (p H = 2) | H_{2 (1 a t m)}, P t$ is ::

0.878 V

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0.642 V

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0.875 V

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0.700 V

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Solution

The correct option is B $0.642 V$
Given
$- l o g [H^{+}] = 2$
$∴ [H]^{+} = 10^{- 2}$

$2 e^{-} + Z n^{2 +} \to Z n$ $E^{\circ} = - 0.76$

$Z n + 2 H^{+} \to Z n^{2 +} + H_{2}$

$∴ E_{c e l l} = - (- 0.76) - \frac{0.059}{2} l o g \frac{[Z n^{2 +}]}{[H^{+}]^{2}}$

$= 0.76 - \frac{0.059}{2} \times 2 p H$

$= 0.76 - \frac{0.059}{2} \times 2 \times 2$

$= 0.642 V$

Option B is correct.

Suggest Corrections

Similar questions

Z n \to Z n^{2 +} + 2 e^{-} (E_{(Z n^{2 +} / Z n)}^{0} = - 0.76 V)

F e \to F e^{2 +} + 2 e^{-} E^{0} = 0.41 V

F e^{2 +} + Z n \to Z n^{2 +} + F e

E^{o}

{Z n}^{2 +} | Z n

- 0.76

Z n ∣ ∣ {Z n}^{2 +} (1 M) ∣ ∣ ∣ ∣ 2 H^{+} (1 M) ∣ ∣ H_{2} (1 a t m)

Z n + 2 H^{+} \to Z n^{2 +} (0.1 M) + H_{2} (1 a t m)

0.28

25^{\circ} C

E_{(Z n^{2 +} | Z n)}^{⊖} = - 0.76 V

Z n (s) / Z n^{2 +} (a q) ∥ C u^{2 +} (a q) / C u (s)

{E^{0}}_{{Z n}^{2 +} / Z n} =

-

{E^{0}}_{{C u}^{2 +} / C u} =

+

{E^{0}}_{c e l l}

K

E^{\circ}

C u_{(s)} + Z n_{(a q)}^{2 +} \to Z n_{(s)} + C u_{(a q)}^{2 +}

E_{C u^{2 +} / C u}^{0} = 0.34 V, E_{Z n^{2 +} / Z n}^{0} = - 0.76 V

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