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Question

E1 and E2 are events in a probability space satisfying the following constraints P(E1)=P(E2);P(E1E2)=1; E1 and E2 are independent then P(E1)=

A
0
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B
14
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C
12
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D
1
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Solution

The correct option is D 1
Let P(E1)=P(E2)=p then using Addition theorem of probability

P(E1E2)=P(E1)+P(E2)P(E1E2)

[ in case of independent events P(E1E2)=P(E1)P(E2)]

1=p+pp2
or p22p+1=0
or p=1

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