(E)-3-bromo-3-hexene when treated with CH3O⊝ in CH3OH gives
A
3- hexyne
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B
2-hexyne
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C
2,3-hexadiene
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D
2,4-hexadiene
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Solution
The correct option is A 2,3-hexadiene (E)−3−bromo−3−hexene when treated with CH3O− in CH3OH gives 2,3−hexadiene. A molecule of HBr is eliminated as shown in the above reaction.