Question

$E$ and $F$ are respectively the mid-point of equal sides $AB$ and $AC$ of $△ABC$
Show that $BF=CE$

Answer 1

Given E and F are mid point of equal sides AB and AC of triangle ABC

In $\Delta ABF$ and $\Delta ACE$

$AB=AC$ (given )

$\angle A=\angle A$ (common angle )

$AF=AE$ (halves of equal sides)

$\therefore \Delta ABF\cong \Delta ACE$ (SAS rule)

$\therefore BF=CF$ (CPCT)