wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

E and F are respectively the mid-points of equal sides AB and AC of ΔABC (see figure) Show that BF=CE

Open in App
Solution

In ΔABF and ΔACE,
AB=AC (Given)
A=A (common angle)
AF=AE (Halves of equal sides)
So, ΔABFΔACE (SAS rule)
Therefore, BF=CE(CPCT)

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Criteria for Similarity of Triangles
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon