E and F are the points on the side PQ and PR respectively of △PQR. For each of the following cases, state that EF∥QR. If True type 1 and for False type 0
PE=4cm, QE=4.5cm, PF=8cm and RF=9cm
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Solution
PEEQ=44.5=89 PFFR=89 Since, PEEQ=PFFR Hence, By converse of equal intercept theorem, EF∥QR