E- for the cell Zn-Zn2-aq-Cu2-aq-Cu is 1-10 v at 25- The equilibrium constant for the reactionZn-Cu2-aq- Cu-Zn2-aq is of the order of-

The Nernst expression for the given cell is: E_cell=E_cell^∘ 0.059nlogZn^2+Cu^2+ 0=1.1 0.0592logK_eq ∴ K_eq=1.94× 10^37 ...

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Standard VII

Chemistry

Equilibrium Constant from Nernst Equation

E∘ for the ce...

Question

$E^{\circ}$ for the cell $Z n | Z n^{2 +} (a q) | | C u^{2 +} (a q) | C u)$ is $1.10 v$ at $25^{\circ}$ . The equilibrium constant for the reaction
$Z n + C u^{2 +} (a q) \to C u + Z n^{2 +} (a q)$ is of the order of:

10^{- 28}

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10^{37}

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10^{18}

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10^{17}

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Solution

The correct option is B $10^{37}$
The Nernst expression for the given cell is:
$E_{c e l l} = E_{c e l l}^{\circ} - \frac{0.059}{n} l o g \frac{Z n^{2 +}}{C u^{2 +}}$
$0 = 1.1 - \frac{0.059}{2} l o g K_{e q}$
$∴ K_{e q} = 1.94 \times 10^{37}$

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Similar questions

E^{\circ}

for the cell,

{Zn(s)|Zn}^{2 +} (aq) | | {Cu}^{2 +} (aq)|Cu(s)

1.10

V at

25^{\circ} C

. The equilibrium constant for the reaction,

Zn(s) + {Cu}^{2 +} (aq) \to Cu(s) + {Zn}^{2 +} (aq)

1.94 \times 10^{x}

. The value of

x

E^{\circ}

for the cell is

Z n | Z n^{2 +} (a q) | | C u^{2 +} (a q) | C u

25^{\circ} C

, the equilibrium constant for the reaction

Z n + C u^{2 +} (a q) ⇌ C u + Z n^{2 +} (a q)

is of the order of

E^{\circ}

for the cell

Z n | Z n^{2 +} (a q) | | C u^{2 +} (a q) | C u is 1.10 V at 25^{\circ} C

. The equilibrium constant for the reaction

Z n + C u^{2 +} (a q) ⇌ C u + Z n^{2 +}

is of the order of:

$E^{0}$ for the cell, $Z n | Z n {^{2 +}}_{(a q)} | | C u {^{2 +}}_{(a q)} | C u$ is $1.10 V$ at $25^{0} C$ . The equilibrium constant for $Z n + C u {^{2 +}}_{(a q)} \to Z n {^{2 +}}_{(a q)} + C u$ the cell reaction is of the order of :

E^{\circ}

for the electrochemical cell,

Z n (s) | Z n^{2 +} 1 M (a q .) ∥ C u^{2 +} 1 M (a q .) | C u (s)

1.10 V

25^{\circ} C

. The equilibrium constant for the cell reaction,

Z n (s) + C u^{2 +} (a q .) ⇌ Z n^{2 +} (a q .) + C u (s)

will be:

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E∘ for the cell Zn|Zn2+(aq)||Cu2+(aq)|Cu) is 1.10 v at 25∘. The equilibrium constant for the reaction Zn+Cu2+(aq)→Cu+Zn2+(aq) is of the order of:

The correct option is B 1037The Nernst expression for the given cell is: Ecell=E∘cell−0.059nlogZn2+Cu2+ 0=1.1−0.0592logKeq ∴Keq=1.94×1037

$E^{\circ}$ for the cell $Z n | Z n^{2 +} (a q) | | C u^{2 +} (a q) | C u)$ is $1.10 v$ at $25^{\circ}$ . The equilibrium constant for the reaction
$Z n + C u^{2 +} (a q) \to C u + Z n^{2 +} (a q)$ is of the order of:

The correct option is B $10^{37}$
The Nernst expression for the given cell is:
$E_{c e l l} = E_{c e l l}^{\circ} - \frac{0.059}{n} l o g \frac{Z n^{2 +}}{C u^{2 +}}$
$0 = 1.1 - \frac{0.059}{2} l o g K_{e q}$
$∴ K_{e q} = 1.94 \times 10^{37}$