E- for the cell Zn-Zn2-aq-Cu2-aq-Cu is 1-10 V at 25-C- The equilibrium constant for the reaction Zn-Cu2-aq- Cu-Zn2- is of the order of-

The Nernst expression for the given cell is E_cell=E_cell^∘=0.059/2log[Zn^2+]/[Cu^2+] nbsp; 0=1.1 0.059/2log K_eq ∴ K_eq=1.94 × 10^37 ...

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Standard VII

Chemistry

Equilibrium Constant from Nernst Equation

E∘ for the ce...

Question

$E^{\circ}$ for the cell $Z n | Z n^{2 +} (a q) | | C u^{2 +} (a q) | C u is 1.10 V at 25^{\circ} C$ . The equilibrium constant for the reaction $Z n + C u^{2 +} (a q) ⇌ C u + Z n^{2 +}$ is of the order of:

10^{- 28}

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10^{37}

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10^{18}

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10^{17}

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Solution

The correct option is B $10^{37}$
The Nernst expression for the given cell is
$E_{c e l l} = E_{c e l l}^{\circ} = \frac{0.059}{2} l o g \frac{[Z n^{2 +}]}{[C u^{2 +}]}$
$0 = 1.1 - \frac{0.059}{2} l o g K_{e q}$
$∴ K_{e q} = 1.94 \times 10^{37}$

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Similar questions

E^{\circ}

for the cell is

Z n | Z n^{2 +} (a q) | | C u^{2 +} (a q) | C u

25^{\circ} C

, the equilibrium constant for the reaction

Z n + C u^{2 +} (a q) ⇌ C u + Z n^{2 +} (a q)

is of the order of

$E^{0}$ for the cell, $Z n | Z n {^{2 +}}_{(a q)} | | C u {^{2 +}}_{(a q)} | C u$ is $1.10 V$ at $25^{0} C$ . The equilibrium constant for $Z n + C u {^{2 +}}_{(a q)} \to Z n {^{2 +}}_{(a q)} + C u$ the cell reaction is of the order of :

E^{\circ}

for the cell

Z n | Z n^{2 +} (a q) | | C u^{2 +} (a q) | C u)

1.10 v

25^{\circ}

. The equilibrium constant for the reaction

Z n + C u^{2 +} (a q) \to C u + Z n^{2 +} (a q)

is of the order of:

E^{\circ}

for the cell,

{Zn(s)|Zn}^{2 +} (aq) | | {Cu}^{2 +} (aq)|Cu(s)

1.10

V at

25^{\circ} C

. The equilibrium constant for the reaction,

Zn(s) + {Cu}^{2 +} (aq) \to Cu(s) + {Zn}^{2 +} (aq)

1.94 \times 10^{x}

. The value of

x

E^{\circ}

for the electrochemical cell,

Z n (s) | Z n^{2 +} 1 M (a q .) ∥ C u^{2 +} 1 M (a q .) | C u (s)

1.10 V

25^{\circ} C

. The equilibrium constant for the cell reaction,

Z n (s) + C u^{2 +} (a q .) ⇌ Z n^{2 +} (a q .) + C u (s)

will be:

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E∘ for the cell Zn|Zn2+(aq)||Cu2+(aq)|Cu is 1.10 V at 25∘C. The equilibrium constant for the reaction Zn+Cu2+(aq)⇌Cu+Zn2+ is of the order of:

The correct option is B 1037The Nernst expression for the given cell is Ecell=E∘cell=0.0592log[Zn2+][Cu2+] 0=1.1−0.0592logKeq ∴Keq=1.94×1037

$E^{\circ}$ for the cell $Z n | Z n^{2 +} (a q) | | C u^{2 +} (a q) | C u is 1.10 V at 25^{\circ} C$ . The equilibrium constant for the reaction $Z n + C u^{2 +} (a q) ⇌ C u + Z n^{2 +}$ is of the order of:

The correct option is B $10^{37}$
The Nernst expression for the given cell is
$E_{c e l l} = E_{c e l l}^{\circ} = \frac{0.059}{2} l o g \frac{[Z n^{2 +}]}{[C u^{2 +}]}$
$0 = 1.1 - \frac{0.059}{2} l o g K_{e q}$
$∴ K_{e q} = 1.94 \times 10^{37}$