E - for the half cells -MnO 2-4 H -2 e - Mn 2-2 H 2 O is 1-23 VFe 3- e - F e 2- is 0-77 VWhich of the following statements is true-A- F e 3- will reduce MnO 2 to Mn 2-B- F e 3- will oxidize Mn 2- to MnO 2C- Mn 2- will oxidize F e 2- to F e 3-D- MnO 2 will oxidize F e 2- to F e 3-

The correct option is D MnO_2 will oxidize Fe^2+ to Fe^3+ nbsp;The overall reaction is: So Fe is getting oxidised from +2 to +3 while Mn is getting reduced ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Standard Electrode Potentials

E ∘ for the h...

Question

$E^{\circ}$ for the half cells :
$M n O_{2} + 4 H^{+} + 2 e^{-} \to M n^{2 +} + 2 H_{2} O i s 1.23 V F e^{3 +} + e^{-} \to F e^{2 +} i s 0.77 V$
Which of the following statements is true?

F e^{3 +}

will reduce

M n O_{2}

M n^{2 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

F e^{3 +}

will oxidize

M n^{2 +}

M n O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

M n O_{2}

will oxidize

F e^{2 +}

F e^{3 +}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

M n^{2 +}

will oxidize

F e^{2 +}

F e^{3 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $M n O_{2}$ will oxidize $F e^{2 +}$ to $F e^{3 +}$
The overall reaction is:

So Fe is getting oxidised from +2 to +3 while Mn is getting reduced from +4 to +2

Suggest Corrections

Similar questions

While $F e^{3 +}$ is stable, $M n^{3 +}$ is not stabe in acid solution because:
$(M n^{3 +} + e^{-} \to M n^{2 +}, E^{\circ} = 1.5 V; O_{2} + 4 H^{+} + 4 e^{-} \to 2 H_{2} O, E^{\circ} = + 1.23 V; F e^{3 +} + e^{-} \to F e^{2 +}, E^{\circ} = 0.77 V)$

Q. While

F e^{3 +}

is stable,

M n^{3 +}

is not stabe in acid solution because:

(M n^{3 +} + e^{-} \to M n^{2 +}, E^{\circ} = 1.5 V; O_{2} + 4 H^{+} + 4 e^{-} \to 2 H_{2} O, E^{\circ} = + 1.23 V; F e^{3 +} + e^{-} \to F e^{2 +}, E^{\circ} = 0.77 V)

Q. Element

F e

has two oxidation states

F e^{2 +}

F e^{3 +}

, the correct order of radii of these ions will be:

Q. Consider the ions

F e^{2 +}, F e^{3 +}, C r^{2 +}, C r^{3 +}, M n^{2 +}, M n^{3 +}

. Strongest oxidizing ion is ?

Join BYJU'S Learning Program

E∘ for the half cells : MnO2+4H++2e−→Mn2++2H2O is 1.23 VFe3++e−→Fe2+ is 0.77 V Which of the following statements is true?

The correct option is C MnO2 will oxidize Fe2+ to Fe3+ The overall reaction is: So Fe is getting oxidised from +2 to +3 while Mn is getting reduced from +4 to +2

$E^{\circ}$ for the half cells :
$M n O_{2} + 4 H^{+} + 2 e^{-} \to M n^{2 +} + 2 H_{2} O i s 1.23 V F e^{3 +} + e^{-} \to F e^{2 +} i s 0.77 V$
Which of the following statements is true?

The correct option is C $M n O_{2}$ will oxidize $F e^{2 +}$ to $F e^{3 +}$
The overall reaction is:

So Fe is getting oxidised from +2 to +3 while Mn is getting reduced from +4 to +2