Question 72 e Find the value of 2 - 3 - 4 - 20- 30- 40

2 × 3 × 4 ÷ 2^0 × 3^0 × 4^0 = 2 × 3 × 4 ÷ 1 × 1 × 1 × 1 = 2 × 3 × 4/1 × 1 × 1 = 2 × 3 × 4 = 24 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VII

Mathematics

Types of Brackets

Question 72 e...

Question

Question 72 (e)

Find the value of
$2 \times 3 \times 4 \div 2^{0} \times 3^{0} \times 4^{0}$

Open in App

Solution

$2 \times 3 \times 4 \div 2^{0} \times 3^{0} \times 4^{0} = 2 \times 3 \times 4 \div 1 \times 1 \times 1 \times 1 = \frac{2 \times 3 \times 4}{1 \times 1 \times 1} = 2 \times 3 \times 4 = 24$

Suggest Corrections

Similar questions

Question 72 (d)

Find the value of
$(2^{0} + 3^{0} + 4^{0}) (4^{0} - 3^{0} - 2^{0})$

Question 72 (f)

Find the value of
$(8^{0} - 2^{0}) \times (8^{0} + 2^{0})$

Q. If the mean of the following frequency distribution is 24, find the value of p. [CBSE 2013]

Class	0−10	10−20	20−30	30−40	40−50
Frequency	3	4	p	3	2

Q. If mean of following data is

215

then find

k

Class	$0 - 10$	$10 - 20$	$20 - 30$	$30 - 40$	$40 - 50$
F	$6$	$4$	$3$	$k$	$2$

If the mean of the following frequency distibution is 24, find the value of p.
$\begin{matrix} Class & 0 - 10 & 10 - 20 & 20 - 30 & 30 - 40 & 40 - 50 Frequency & 3 & 4 & p & 3 & 2 \end{matrix}$

Join BYJU'S Learning Program

Question 72 (e) Find the value of 2×3×4÷20×30×40

2×3×4÷20×30×40=2×3×4÷1×1×1×1=2×3×41×1×1=2×3×4=24

Question 72 (e)

Find the value of
$2 \times 3 \times 4 \div 2^{0} \times 3^{0} \times 4^{0}$

$2 \times 3 \times 4 \div 2^{0} \times 3^{0} \times 4^{0} = 2 \times 3 \times 4 \div 1 \times 1 \times 1 \times 1 = \frac{2 \times 3 \times 4}{1 \times 1 \times 1} = 2 \times 3 \times 4 = 24$