Question 66 (e)

Find the value of the given polynomial at a = -2 and b = 3.

$\frac{a^{2} + b^{2}}{3}$

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Solution

Given, a = -2 and b = 3
So, putting a = -2 and b = 3 in the given expression, we get
$\frac{a^{2} + b^{2}}{3} = \frac{(- 2)^{2} + (3)^{2}}{3} = \frac{4 + 9}{3} = \frac{13}{3}$

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Question 66 (h)

Find the value of the given polynomial at a = -2 and b = 3.

$a^{2} + b^{2} - a b - b^{2} - a^{2}$

Question 66 (f)

Find the value of the given polynomial at a = -2 and b = 3.

$\frac{a^{2} - b^{2}}{3}$

Question 66 (b)

Find the value of the given polynomial at a = -2 and b = 3.

$a^{2} - 2 a b + b^{2}$

Question 66 (c)

Find the value of the given polynomial at a = -2 and b = 3.

$a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3}$

Question 66 (g)

Find the value of the given polynomial at a = -2 and b = 3.

$\frac{a}{b} + \frac{b}{a}$

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