E is a point outside the circle as shown. ME and NE are tangents drawn to the circle from this point. Quadrilateral OMEN is symmetrical with respect to OE.
A
True
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B
False
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Solution
The correct option is A True In △OME and △ONE, OE = OE [common side] ME = EN [Tangents are equal] OM = ON [Radii] So, by SSS criterion, △OME≅△ONE i.e. the triangles on either side of OE are congruent. Hence OMEN is symmetrical with respect to OE.