You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Faraday's First Law

ENa + /Nas0 =...

Question

$E_{N a^{+} / N a (s)}^{0} = - 2.71 V$ , $E_{M g^{2 +} / M g (s)}^{0} = - 2.37 V$ , $E_{F e^{2 +} / F e (s)}^{0} = - 0.44 V$ and $E_{C r^{3 +} / C r (s)}^{0} = - 0.41 V$ Based on this data, state which of the following is the weakest reducing agent.

N a^{+}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

N a

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C r

No worries! We‘ve got your back. Try BYJU‘S free classes today!

F e^{2 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $N a^{+}$
$M + n X \to M^{n +} + n X^{-}$
So higher the $E_{M / M^{n - 1}}^{\circ}$ , stronger is that reducing agent.
$E_{N a / N a^{+}}^{\circ} = 2.71$ is largest
$∴$ Na is strongest reducing agent
$∴ N a^{+}$ is weakest reducing agent $E_{N a^{+} / N a}^{\circ}$ is least

Suggest Corrections

Similar questions

Q. Given that

E_{K^{+} / K}^{\circ} = - 2.93 V; E_{F e^{2 +} / F e}^{\circ} = - 0.44 V; E_{Z n^{2 +} / Z n}^{\circ} = - 0.76 V; E_{C u^{+ 2} / C u}^{\circ} = 0.34 V

Based on this data, which of the following is the strongest reducing agent?

Q. Calculate the emf of the cell

C r | C r^{3 +} (0.1 M) | | F e^{2 +} (0.01 M) | F e

(Given:

E_{C r^{3 +} / C r}^{\circ} = - 0.75 v o l t; E_{F e^{2 +} / F e}^{\circ} = - 0.45 v o l t)

Q. Given

E_{C r^{3 +} |}^{o}

_{Cr}

= - 0.72 V, E_{F e^{2 +} | F e}^{o} = - 0.42

The potential for the cell

| C r^{3 +} (0.1 M) ∥ F e^{2 +} (0.01 M) |

Fe is:

Q. Which of the following transformations can be carried out by using HI as a reducing agent, under acidic conditions?[Given:

I_{2} (s) \to 2 I^{-}

;

E^{⊖} = 0.54 V]

(i)

C u^{+} \to C u (s); E^{⊖} = 0.52 V

(ii)

C r^{3 +} \to C r^{2 +}; E^{⊖} = - 0.41 V

(iii)

F e^{3 +} \to F e^{2 +}; E^{⊖} = 0.77 V

(iv)

F e^{2 +} \to F e (s); E^{⊖} = - 0.44 V

$E^{\circ}$ value of $M g^{2 +} | M g, Z n^{2 +} | Z n$ and $F e^{2 +} | F e$ are – 2.37 V, - 0.76 V and 0.44 V respectively. Which of the following is correct?

Join BYJU'S Learning Program

E0Na+/Na(s)=−2.71V , E0Mg2+/Mg(s)=−2.37V, E0Fe2+/Fe(s)=−0.44V and E0Cr3+/Cr(s)=−0.41VBased on this data, state which of the following is the weakest reducing agent.

The correct option is A Na+M+nX→Mn++nX−So higher the E∘M/Mn−1 , stronger is that reducing agent.E∘Na/Na+=2.71 is largest∴ Na is strongest reducing agent∴Na+ is weakest reducing agent E∘Na+/Na is least

$E_{N a^{+} / N a (s)}^{0} = - 2.71 V$ , $E_{M g^{2 +} / M g (s)}^{0} = - 2.37 V$ , $E_{F e^{2 +} / F e (s)}^{0} = - 0.44 V$ and $E_{C r^{3 +} / C r (s)}^{0} = - 0.41 V$ Based on this data, state which of the following is the weakest reducing agent.