You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Faraday's Second Law

Eo for Mg2+...

Question

$E^{o}$ for $M g^{2 +} / M g = - 2.37 V, Z n^{2 +} / Z n = - 0.76 V$ and $F e^{2 +} / F e = - 0.44 V$

Which of the following statement is correct?

Zn reduces

F e^{2 +}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Zn reduces

M g^{2 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

M g

oxidises

F e

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Z n

oxidises

F e

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A Zn reduces $F e^{2 +}$
Higher the negative value of reduction potential, the higher will be the reducing power.

Hence, $M g$ reduces both $Z n^{2 +}$ and $F e^{2 +} . Z n$ can reduce $F e^{2 +}$ but not $M g^{2 +}$ .

Similarly, $F e^{2 +}$ can oxidise $Z n$ and $M g$ both.

Suggest Corrections

Similar questions

$E^{\circ}$ value of $M g^{2 +} | M g, Z n^{2 +} | Z n$ and $F e^{2 +} | F e$ are – 2.37 V, - 0.76 V and 0.44 V respectively. Which of the following is correct?

Q. SRP values of

M g^{2 +} | M g

F e^{2 +} | F e

and

Z n^{2 +} | Z n

are

- 2.37 V, - 0.44 V

and

- 0.76 V

respectively. The correct statement is:

Standard reduction potential values for the electrodes are given below.

$M g^{2 +} + 2 e^{-} \to M g;$ $E_{r e d}^{o} =$ $- 2.37$ V

$Z n^{2 +} + 2 e^{-} \to Z n;$ $E_{r e d}^{o} =$ $- 0.76$ V

$F e^{2 +} + 2 e^{-} \to F e;$ $E_{r e d}^{o} =$ $- 0.44$ V

Which of the following statement is correct ?

Q. Given the standard half-cell potentials

(E^{o})

of the following as

Z n = Z n^{2 +} + 2 e^{-}

;

E^{o} = + 0.76

F e = F e^{2 +} + 2 e^{-}

;

E^{o} = + 0.41

Then the standard e.m.f. of the cell with the reaction

F e^{2 +} + Z n \to Z n^{2 +} + F e

is?

Q. Standard reduction potential values for the electrodes are given below

M g^{2 +} + 2 e^{-} \to M g; E^{0} = - 2.37 V

Z n^{2 +} + 2 e^{-} \to Z n; E^{0} = - 0.76 V

F e^{2 +} + 2 e^{-} \to F e; E^{0} = - 0.44 V

Which of the following statements is correct?

Join BYJU'S Learning Program

Eo for Mg2+/Mg=−2.37V,Zn2+/Zn=−0.76V and Fe2+/Fe=−0.44V Which of the following statement is correct?

The correct option is A Zn reduces Fe2+Higher the negative value of reduction potential, the higher will be the reducing power. Hence, Mg reduces both Zn2+ and Fe2+.Zn can reduce Fe2+ but not Mg2+. Similarly, Fe2+ can oxidise Zn and Mg both.

$E^{o}$ for $M g^{2 +} / M g = - 2.37 V, Z n^{2 +} / Z n = - 0.76 V$ and $F e^{2 +} / F e = - 0.44 V$

Which of the following statement is correct?

The correct option is A Zn reduces $F e^{2 +}$
Higher the negative value of reduction potential, the higher will be the reducing power.

Hence, $M g$ reduces both $Z n^{2 +}$ and $F e^{2 +} . Z n$ can reduce $F e^{2 +}$ but not $M g^{2 +}$ .

Similarly, $F e^{2 +}$ can oxidise $Z n$ and $M g$ both.