E- for Cr3- - 3e- - Cr and Cr3- - e- - Cr2- are -0-74 V and -0-40 V- respectively- E- for the reaction is- Cr-2 - 2e- - Cr

The correct option is A 0.91 V Cr^3+ + 3e^ → Cr; Cr^3+ + e^ → Cr^2+; Cr^2+ + 2e^ → Cr; E^⊖_3 = n_1 E^⊖_1 n_2 E^⊖_2n_ ...

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Nernst Equation

E⊖ for Cr3+ +...

Question

$E^{⊖} f o r C r^{3 +} + 3 e^{-} \to C r a n d C r^{3 +} + e^{-} \to C r^{2 +}$ are $- 0.74 V$ and $- 0.40 V$ , respectively. $E^{⊖}$ for the reaction is: $C r^{+ 2} + 2 e^{-} \to C r$

- 0.91 V

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+ 0.91 V

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1.14 V

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+ 0.34 V

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C r + 2 C r^{3 +} ⇌ 3 C r^{2 +}

E^{⊖}

Δ G^{⊖}

E_{C r^{3 +} | C r^{2 +}}^{⊖} = - 0.40 V, E_{C r^{3 +} | C r}^{⊖} = - 0.74 V, a n d E_{C r^{2 +} | C r}^{⊖} = - 0.91 V

E^{0}

C r^{2 +} (a q) + 2 e^{-} \to C r (s)

E^{0}

C r^{3 +} (a q) + e^{-} \to C r^{2 +} (a q); E^{0} = - 0.41 V

C r^{3 +} (a q) + 3 e^{-} \to C r (s); E^{0} = - 0.74 V

F e^{+ 2} + 2 e \to F e; E^{o} = 0.44 V

F e^{+ 3} + 1 e \to F e^{+ 2}; E^{o} = + 0.77 V

S n^{+ 4} + 2 e \to S n^{+ 2}; E^{o} = + 0.13 V

I_{2} + 2 e \to 2 I; E^{o} = + 0.54 V

C r^{3 +} + 3 e \to C r; E^{o} = 0.74 V

Z n^{2 +} + 2 e^{-} \to Z n; (- 0.762 V

C r^{3 +} + 3 e^{-} \to C r; (- 0.74 V

2 H^{+} + 2 e^{-} \to H_{2}; (0.0 V

F e^{3 +} + e^{-} \to F e^{2 +}; (0.77 V

E_{C r^{3 +} / C r}^{\circ} = - 0.72 V, E_{F e^{2 +} / F e}^{\circ} = - 0.42 V

C r | C r^{3 +} (0.1 M) | | F e^{2 +} (0.01 M) | F e

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