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Electrochemical Series

E⊖ of Mg2+ | ...

Question

$E^{⊖} o f M g^{2 +} | M g, Z n^{2 +} | Z n,$ and $F e^{2 +} | F e$ are $- 2.37 V$ , $- 0.76 V$ , and - $0.44 V$ , respectively. Which of the following is correct ?

M g

oxidizes

F e

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Z n

oxidizes

F e

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Z n

reduces

M g^{2 +}

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Z n

reduces

F e^{2 +}

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Solution

The correct option is B $Z n$ reduces $F e^{2 +}$
Lower is the reduction potential, higher is the tendency to oxidise so
$M g$ reduces $Z n^{2 +}$ to $Z n$ and $Z n$ reduces $F e^{2 +}$ to $F e$ .

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Similar questions

$E^{\circ}$ value of $M g^{2 +} | M g, Z n^{2 +} | Z n$ and $F e^{2 +} | F e$ are – 2.37 V, - 0.76 V and 0.44 V respectively. Which of the following is correct?

Q. SRP values of

M g^{2 +} | M g

F e^{2 +} | F e

and

Z n^{2 +} | Z n

are

- 2.37 V, - 0.44 V

and

- 0.76 V

respectively. The correct statement is:

E^{o}

for

M g^{2 +} / M g = - 2.37 V, Z n^{2 +} / Z n = - 0.76 V

and

F e^{2 +} / F e = - 0.44 V

Which of the following statement is correct?

Q. Standard reduction potential values for the electrodes are given below

M g^{2 +} + 2 e^{-} \to M g; E^{0} = - 2.37 V

Z n^{2 +} + 2 e^{-} \to Z n; E^{0} = - 0.76 V

F e^{2 +} + 2 e^{-} \to F e; E^{0} = - 0.44 V

Which of the following statements is correct?

Q. The standard electrode potential of the half cells is given below:

Z n^{2 +} + 2 e^{-} \to Z n; E = - 0.76 V

F e^{2 +} + 2 e^{-} \to F e; E = - 0.44 V

The emf of the cell

F e^{2 +} = Z n^{-} \to Z n^{2 +} + F e

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E⊖ofMg2+|Mg,Zn2+|Zn, and Fe2+|Fe are −2.37V, −0.76V, and -0.44V, respectively. Which of the following is correct ?

The correct option is B Zn reduces Fe2+Lower is the reduction potential, higher is the tendency to oxidise soMg reduces Zn2+ to Zn and Zn reduces Fe2+ to Fe.

$E^{⊖} o f M g^{2 +} | M g, Z n^{2 +} | Z n,$ and $F e^{2 +} | F e$ are $- 2.37 V$ , $- 0.76 V$ , and - $0.44 V$ , respectively. Which of the following is correct ?

The correct option is B $Z n$ reduces $F e^{2 +}$
Lower is the reduction potential, higher is the tendency to oxidise so
$M g$ reduces $Z n^{2 +}$ to $Z n$ and $Z n$ reduces $F e^{2 +}$ to $F e$ .