wiz-icon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

e|sinx|+e|sinx|+4a=0 will have exactly four different solutions in [0,2π] if


A

a R

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

a [e4,14]

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

a [1e24e],

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

None

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D

None


Let e|sinx|=tt[1,e]t+1t+4a=0t2+4at+1=0. This quadratic equation has 2 distinct roots in [1,e] as x [0,2π]16a24>0, 1+4a+10, e2+4at+10, 1<2a<e|a|>12, a12, a1e24e, e2<a<12 No value satisfy the above inequalities simultaneously.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon