Question 3(e)
Solve the following equations:
28=4+3(t+5)

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Solution

$28 = 4 + 3 (t + 5) \Rightarrow 28 - 4 = 3 (t + 5)$
$\Rightarrow 24 = 3 (t + 5) \Rightarrow \frac{24}{3} = t + 5 \Rightarrow 8 = t + 5 \Rightarrow 8 - 5 = t \Rightarrow 3 = t \Rightarrow t = 3$

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Solve the following:

$\frac{3 t + 5}{4} - 1 = \frac{4 t - 3}{5}$

t - (2 t + 5) - 5 (1 - 2 t) = 2 (3 + 4 t) - 3 (t - 4)

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