E Taking x - -4-9- y - 5-12 and z - 7-18- find The reciprocal of x - y-

Given, x = 4/9, y = 5/12 and z = 7/18 Here, x + y = 4/9 + 5/12 = 4 × 4+5 × 3/36 = 1/36 [∵ LCM of 12 and 9 = 36] ∴ Reciprocal of (x + y ) = 1/ 1/36 = ...

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Standard VII

Mathematics

Addition of Rational Numbers

e Taking x = ...

Question

Question 94 (e)

Taking $x = \frac{- 4}{9}, y = \frac{5}{12}$ and $z = \frac{7}{18},$ find
The reciprocal of x + y.

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Solution

Given, $x = \frac{- 4}{9}, y = \frac{5}{12} a n d z = \frac{7}{18}$
Here, $x + y = \frac{- 4}{9} + \frac{5}{12} = \frac{- 4 \times 4 + 5 \times 3}{36} = - \frac{1}{36}$ [ $∵$ LCM of 12 and 9 = 36]
$∴$ Reciprocal of $(x + y) = \frac{1}{\frac{- 1}{36}} = - 36$

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Similar questions

Question 94 (f)

Taking $x = \frac{- 4}{9}, y = \frac{5}{12}$ and $z = \frac{7}{18}$ , find
The sum of reciprocals of x and y

Question 94 (b)

Taking $x = \frac{- 4}{9}, y = \frac{5}{12}$ and $z = \frac{7}{18},$ find
The rational number which subtracted from y gives z.

Question 94 (c)

Taking $x = \frac{- 4}{9}, y = \frac{5}{12}$ and $z = \frac{7}{18},$ find
The rational number which when added to z gives us x.

Question 94 (k)

Taking $x = \frac{- 4}{9}, y = \frac{5}{12}$ and $z = \frac{7}{18},$ find
$x - (y + z)$

Question 94 (i)

Taking $x = \frac{- 4}{9}, y = \frac{5}{12}$ and $z = \frac{7}{18},$

Find $x + (y + z)$ .

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Addition of Rational Numbers

Standard VII Mathematics

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Question 94 (e) Taking x=−49,y=512 and z=718, find The reciprocal of x + y.

Given, x=−49,y=512 and z=718 Here, x+y=−49+512=−4×4+5×336=−136 [∵ LCM of 12 and 9 = 36] ∴ Reciprocal of (x+y)=1−136=−36

Question 94 (e)

Taking $x = \frac{- 4}{9}, y = \frac{5}{12}$ and $z = \frac{7}{18},$ find
The reciprocal of x + y.

Given, $x = \frac{- 4}{9}, y = \frac{5}{12} a n d z = \frac{7}{18}$
Here, $x + y = \frac{- 4}{9} + \frac{5}{12} = \frac{- 4 \times 4 + 5 \times 3}{36} = - \frac{1}{36}$ [ $∵$ LCM of 12 and 9 = 36]
$∴$ Reciprocal of $(x + y) = \frac{1}{\frac{- 1}{36}} = - 36$