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Question

Eα=(cosαsinαsinα cosα]Eβ=(cosβsinβsinβcosβ] then find,Eα×Eβ ?

A
E(αβ)
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B
E(α+β)
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C
E(α×β)
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D
E(α/β)
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Solution

The correct option is B E(α+β)
Eα×Eβ=(cos(α)sin(α)sin(α) cos(α)]×(cos(β)sin(β)sin(β)cos(β)] =(cos(α)cos(β)sin(α)sin(β)cos(α)sin(β)+sin(α)cos(β)sin(α)cos(β)cos(α)sin(β)sin(α)sin(β)+cos(α)cos(β)]=(cos(α+β)sin(α+β)sin(α+β)cos(α+β)]=E(α+β)option (b) is correct

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