Question

Each angle of equilateral triangle is ${60}^0$. If true enter 1 else 0.

Answer 1

Consider an equilateral triangle $ABC$, $\angle A=\angle B=\angle C=x$
Sum of angles = ${180}^o$
$\angle A+\angle B+\angle C={180}^o$
$x+x+x={180}^o$

$3x={180}^o$
$x={60}^o$
Each angle of Equilateral Triangle is ${60}^{\circ }$