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Question
Each edge of a cube is increased by 50%. Find the percentage increase in the surface area of a cube .
Each edge of a cube is increased by 50%. Find the percentage increase in the surface area of a cube .
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Solution
Let original edge length of cube is x units.
Original surface area of cube = 6x^2 square units.
If edge length of cube is increased by 50%, New edge length of cube = x + (50/100) x = x + 0.5x = 1.5x units
New surface area of cube = 6 * (1.5x)^2 = 13.5x^2 square units.
Percentage increase in surface area =
((New Surace Area - Original Surface Area) /Original Surface Area) *100
= ((13.5x^2 - 6x^2)/6x^2) *100
= 125%
Let original edge length of cube is x units.
Original surface area of cube = 6x^2 square units.
If edge length of cube is increased by 50%, New edge length of cube = x + (50/100) x = x + 0.5x = 1.5x units
New surface area of cube = 6 * (1.5x)^2 = 13.5x^2 square units.
Percentage increase in surface area =
((New Surace Area - Original Surface Area) /Original Surface Area) *100
= ((13.5x^2 - 6x^2)/6x^2) *100
= 125%
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