wiz-icon
MyQuestionIcon
MyQuestionIcon
9
You visited us 9 times! Enjoying our articles? Unlock Full Access!
Question

Each edge of a cube is increased by 50%, then percentage increase in its surface area =.

A
125%
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
110%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
150%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 125%
Let the edge =a cm.
New measure of the edges after increase =a+50 %a=a+a2=3a2
Total surface area of the original cube =6a2

Total surafec area of the new cube
=6×(3a2)2=6×9a24=94×6a2=2.25×6a2

=2.25 × Total surface area of the original cube

Increase in the area
= New total surface area - orignal suface area
=(2.251)×6a2=1.25×6a2

Total surface area of the original cube
=1.25 × Total surface area of the original cube.

Percentage increase in surface area =125 %.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Surface Area and Volume
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon