Question

Each figure given below shows a pair of parallel lines cut by a traversal. For each case, find a and b, giving reasons.

Answer 1

$\begin{array}{c}Infigure\left(1\right)\\ a={180}^0-{140}^0\\ a={40}^0\\ b={40}^0\left(alternateinteriorangle\right)\\ Infigure\left(2\right)\\ b+{60}^0={180}^0\left(anglemadebystraightline\right)\\ b={120}^0\\ x={60}^0\\ a=x\left(interiorangle\right)\\ a={60}^0\end{array}$