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Question

Each interior angle of a regular polygon is 1440. Find the interior angle of a regular polygon which has double the number of sides as the first polygon.

A
1000
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B
1600
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C
360
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D
1620
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Solution

The correct option is D 1620
Since each interior angle of the first polygon =144o
Each exterior angle of the first polygon =180144
=36o
The number of sides of the first polygon =36036=10
The number of sides of the second polygon =2×10=20
Each exterior angle of the second polygon =360o20=18o
Each interior angle of the second polygon =180o18o=162o

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