Question

Each letter of the word "INDEPENDENT" is written on individual cards. The cards are placed in a box and mingled thoroughly. A card with letter 'N' is removed from the box. Now find the probability of picking a card with a consonant ?

• A. $\frac{7}{11}$
• B. $\frac{7}{10}$
• C. $\frac{3}{5}$
• D. $\frac{2}{5}$

Answer 1

Answer: (C)

$\frac{3}{5}$

The total number of letters in the word INDEPENDENT is 11.

Out of them 4 are vowels and the rest are (11-4)=7 are consonants.

N, which is a consonant, is removed.

$\therefore$ the number of the letters or the probability space=11-1=10

and the number of consonants or the favourable events=7-1=6.

$\therefore$ P(consonant)=$\frac{Numberoffavourableevents}{probabilityspace}=\frac{6}{10}=\frac{3}{5}$