Each of the numbers 1, 2, 3 and 4 is substituted, in some order for p, q, r and s. The greatest possible value of $p^{q} + r^{s}$ is:

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Solution

The correct option is D 83
Let p = 2, q = 1, r = 3, s = 4
Then, substituting them in the equation:
$p^{q} + r^{s} = (2)^{1} + (3)^{4} = 2 + 81 = 83$

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Each of the numbers 1, 2, 3 and 4 is substituted, in some order for p, q, r and s. The greatest possible value of $p^{q} + r^{s}$ is:

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