Question

Each of the resistors shown in the figure (32-E11) has a resistance of 10 Ω and each of the batteries has an emf of 10 V. Find the currents flowing through the resistors a and b in the two circuits.

Answer 1

(a)
From the figure,
Potential difference between the two ends of resistor a = 10 V
Resistance of resistor a =10 Ω
∴ Current through a = $\frac{10}{10}=1\mathrm{A}$
Since the two batteries are connected opposite each other,
potential difference between the terminals of b = 10 – 10 = 0 V
∴ Current through b = 0 A
(b)


From the figure,
Potential difference between the two ends of resistor a = 10 V.
Resistance of resistor a =10 Ω
∴ Current through a = $\frac{10}{10}=1\mathrm{A}$
Since the two batteries are again connected opposite to each other,
Potential difference between terminal of b = 10 – 10 = 0 V
∴ Current through b = 0 A