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Question

Each of the two blocks shown in the figure has a mass \(m\). The coefficient of friction for all surfaces in contact is \(\mu\). A horizontal force \(P\) is applied to move the bottom block. The value of \(P\), for which acceleration of block \(A\) is same in both cases is

A
2μmg
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B
μmg
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C
3μmg
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D
23μmg
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Solution

The correct option is A 2μmg

a1=P(μmg+2μmg)m
=(P3μmgm)
Tf1=ma2
PTf2f1=ma2
Pf22f1=2ma2
a2=(P4μmg2m)
For 2P6μmg=P4μmg
P=2μmg

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