Question

Each of the two equal sides of an isosceles right triangle is 10 cm long. Its area is
(a) $5\sqrt{10}{\mathrm{cm}}^2$
(b) 50 cm²
(c) $10\sqrt{3}{\mathrm{cm}}^2$
(d) 75 cm²

Answer 1

(b) 50 cm²
Here, the base and height of the triangle are 10 cm and 10 cm, respectively.
Thus, we have:
$$\begin{gathered} \mathrm{Area}\mathrm{of}\mathrm{triangle}=\frac{1}{2}\times \mathrm{Base}\times \mathrm{Height} \\ =\frac{1}{2}\times 10\times 10 \\ =50{\mathrm{cm}}^2 \end{gathered}$$