Question

Each of two angles of a triangle is ${60}^0$ and the inclined side is $4$ inches. The area of the triangle, in square inches, is :

• A. $8\sqrt{3}$
• B. $8$
• C. $4\sqrt{3}$
• D. $4$
• E. $2\sqrt{3}$

Answer 1

The correct option is C $4\sqrt{3}$

The given triangle is equilateral triangle.

Then area of equilateral triangle$=\frac{\sqrt{3}}{4}{a}^2=\frac{\sqrt{3}}{4}\times 4\times 4=4\sqrt{3}$ sq. inches.