Question

Each of two groups of tourists has $60$ people. If $\frac{3}{4}$ of the first group and $\frac{2}{3}$ of the second group board buses to travel to a museum, how many more people of the first group board buses than that of the second group?

• A. $2$
• B. $4$
• C. $5$
• D. $40$

Answer 1

The correct option is C $5$

Remaining people of first group $=60-\frac{3\times 60}{4}=15$.

Similarly,

Remaining people of second group $=60-\frac{2\times 60}{3}=20$.

Hence, the number of people of the first group who board buses more than that of the second group $=20-15=5$. Hence, C is the right option.