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Question

Each plate of a parallel plate air capacitor has area S=5×103m2 and the distance between the plates is d=8.80mm. Plate A has positive charge q1=+1010C, and plate B has charge q2=+2×1010C. A battery of emf E=10V has its positive terminal connected to plate A and the negative terminal to plate B. Energy supplied by the battery is :
(Given ε0=8.8×112Nm2C2)

A
109J
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B
5×109J
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C
50×109J
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D
25×109J
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Solution

The correct option is A 109J
C=ε0Ad=8.8×1012×5×1038.8×103=5×1012F
Charge on the plate after connection with the battery is: q=CV=5×1012×10=50pC

Charge supplied by the battery is: Δq=(50+50)pC=100pC

Energy supplied by the battery is: Ubattery=ΔqV=100×10=1000pJ =109J

172540_155337_ans_f57f5d07012749f894ed40b6359250c6.png

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