Question

Each resistance of given figure is of $10\Omega .$ Then current I through cell of 40 V isA. [Write upto 2 digits after the decimal.]

Answer 1

Same network on other side in parallel $\Rightarrow \frac{1}{R_{eq}}=\frac{9}{100}+\frac{9}{100}\Rightarrow R_{eq}=\frac{100}{18}\Omega$
$i=\frac{V}{R_{eq}}=7.2A$