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Question

Each side of a rhombus is 10 cm. If one its diagonals is 16 cm find the length of the other diagonal.

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Solution

We know that a quadrilateral is said to a rhombus if all sides of the quadrilateral are equal. Diagonals of a rhombus bisect each other at right angles.

Quadrilateral ABCD is a rhombus and diagonals AC and BD intersect at point O.

As we defined above, we get , , and angle .

We are given that AB = 10 cm and AC = 16 cm. Now we will find length of BD.

As we know the definition of rhombus we get AB = BC = CD = AD.

Therefore, we get, AB = BC = CD = AD = 10 cm

Also we know that diagonals of rhombus bisect each other at right angles therefore, we get,

,

and

Here, we know the length of AC therefore, we get, .

Now we will use Pythagoras theorem in the right angled triangle AOD as below,

…......(1)

Now we will substitute the values of AD and AO in equation (1) we get,

…......(2)

Now we will subtract 64 from both sides of the equation (2)

Now we will take the square root.

OD = 6

We know that

Therefore, length of the other diagonal is .


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