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Question

Each side of a square is 0.9m long. The charges at its corners are 2μC,+3μC,4μC and +5μC.Determine the electric potential at the centre of the square.

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Solution

(AC)2=(BD)2=a2+a2$AC)=(BD)=2a2AC=BD=2a,a=0.9mAO=BO=CO=DO=AC2
AO=BO=CO=DO=0.922=0.92
Electric potential at centre
V0=14πε0[2×106AO+3×106BO4×106CO+5×106DO]V0=9×109×1060.92[2+34+5]V0=9×103×10×29[2]V0=2×1.414×104V0=2.828×104volt
1763125_1836201_ans_238d5ec6b87442ba8e72d20b1b89e6f2.png

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