Question

Each side of a square tile is \(60~cm\). How many tiles will be required to cover the floor of a hall with length \(= 50~m\) and breadth \(= 36~m\).

Answer 1

Given,
Length of each side of the square tile \(= 60~cm\)
We know that, \(100~cm = 1~m\)
Therefore, \(60~cm = 0.6~m\)
The area of the square tile is given by:
Area\(=(\text{side})^2\)
\(\Rightarrow \text{Area}=0.6\times0.6=0.36~m^2\)

Given,
The rectangular floor of the hall,
Length \(= 50~m\) &
Breadth \(= 36~m\)
The area of the rectangular floor of the hall is given by:
\(=(\text{Lenght}\times\text{Breath})\)
\(=50\times36\)
\(=1800~m^2\)

Number of tiles
\(=\dfrac{\text{Area of the floor}}{\text{Area of the tile}}\)
\(=\dfrac{1800}{0.36}\times\dfrac{100}{100}\)
\(=\dfrac{180000}{36}=5000\)
Therefore, the number of square tiles required would be \(5000\) .