Each side of an equilateral triangle is 6-3 cm then the diameter of the escribed circle is

The correct option is A 18 cm 2s = a+b+c = 6√(3)+6√(3)+6√(3) = 18√(3) s = 9√(3) #10; #10; #10; #10; 2r_1 = 2s tanA2 = 2× 9√(3)× # ...

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Standard XII

Physics

Thermal Expansion

Each side of ...

Question

Each side of an equilateral triangle is $6 \sqrt{3} c m$ then the diameter of the escribed circle is

18 c m

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9 \sqrt{3} c m

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9 c m

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18 \sqrt{3} c m

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Solution

The correct option is A $18 c m$
$2 s = a + b + c = 6 \sqrt{3} + 6 \sqrt{3} + 6 \sqrt{3} = 18 \sqrt{3}$
$⟹ s = 9 \sqrt{3}$

$2 r_{1} = 2 s tan \frac{A}{2} = 2 \times 9 \sqrt{3} \times \frac{1}{\sqrt{3}} = 18$

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Each side of an equilateral triangle is 6√3cm then the diameter of the escribed circle is

The correct option is A 18cm2s=a+b+c=6√3+6√3+6√3=18√3⟹s=9√3 2r1=2stanA2=2×9√3×1√3=18

Each side of an equilateral triangle is $6 \sqrt{3} c m$ then the diameter of the escribed circle is

The correct option is A $18 c m$
$2 s = a + b + c = 6 \sqrt{3} + 6 \sqrt{3} + 6 \sqrt{3} = 18 \sqrt{3}$
$⟹ s = 9 \sqrt{3}$

$2 r_{1} = 2 s tan \frac{A}{2} = 2 \times 9 \sqrt{3} \times \frac{1}{\sqrt{3}} = 18$