Question

Each side of given cube has resistance of $1\Omega$, then equivalent resistance of cube between corner A and B in $\Omega$ is
(Answer upto two decimal places)

Answer 1

After naming currents in branches, we get
$\Rightarrow 4i_3=i_2-i_3\Rightarrow 5i_3=i_2$
Also,
$i_2+(i_2-i_3)+i_2=i_1$
$3i_2-\frac{i_2}{5}=i_1\Rightarrow \frac{14}{5}{i}_2=i_1$


$\epsilon =(2i_2+i_1)R_{eq}.......\left(i\right)\epsilon =i_1\times \mathrm{1............}\left(ii\right)$

By, $\left(i\right)$ and $\left(ii\right)$:
$i_1=(2\times \frac{5}{14}{i}_1+i_1)R_{eq}\Rightarrow R_{eq}=\frac{14}{24}\Omega =0.583\Omega$