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Question

Each side of given cube has resistance of 1 Ω, then equivalent resistance of cube between corner A and B in Ω is
(Answer upto two decimal places)

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Solution

After naming currents in branches, we get
4i3=i2i35i3=i2
Also,
i2+(i2i3)+i2=i1
3i2i25=i1145i2=i1


ε=(2i2+i1)Req.......(i)ε=i1×1............(ii)

By, (i) and (ii):
i1=(2×514i1+i1)ReqReq=1424 Ω=0.583 Ω

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