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Simple Circuit

Each side of ...

Question

Each side of regular polygon of $n$ sides has a resistance $R$ . The equivalent resistance between any two adjacent vertices is

n R

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\frac{R}{n}

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\frac{(n - 1) R}{n}

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\frac{n}{n - 1} R

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Solution

The correct option is C $\frac{(n - 1) R}{n}$
For calculating equivalent resistance between two vertices we can consider $R$ is parallel with the series combination of $(n - 1)$ resistors.

Now for parallel combination
$R_{e q} = \frac{R \times (n - 1) R}{R + (n - 1) R}$
$= (\frac{n - 1}{n}) R$

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Each side of regular polygon of n sides has a resistance R. The equivalent resistance between any two adjacent vertices is

The correct option is C (n−1)RnFor calculating equivalent resistance between two vertices we can considerR is parallel with the series combination of (n−1) resistors. Now for parallel combination Req=R×(n−1)RR+(n−1)R =(n−1n)R

Each side of regular polygon of $n$ sides has a resistance $R$ . The equivalent resistance between any two adjacent vertices is

The correct option is C $\frac{(n - 1) R}{n}$
For calculating equivalent resistance between two vertices we can consider $R$ is parallel with the series combination of $(n - 1)$ resistors.

Now for parallel combination
$R_{e q} = \frac{R \times (n - 1) R}{R + (n - 1) R}$
$= (\frac{n - 1}{n}) R$