EAN of central metal in the complexes $K_{2} [N i (C N)_{4}], [C u (N H_{3})_{4}] S O_{4}$ and $K_{2} (P t C l_{6})$ are x, y and z respectively. Calculate the value of $\frac{x + y + z}{5}$ .

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Solution

Effective Atomic Number (EAN) = atomic no. - oxidiation state of central metal atom + 2 (no. of ligands)
$K_{2} [N i (C N)_{4}] : E A N = 28 - 2 + 2 \times 4 = 34 [C u (N H_{3})_{4}] S O_{4} : E A N = 29 - 2 + 2 \times 4 = 35 K_{2} [P t C l_{6}] : E A N = 78 - 4 + 2 \times 6 = 86 x = 34, y = 35, z = 86 S o, \frac{x + y + z}{5} = \frac{34 + 35 + 86}{5} = 31$

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Similar questions

Q. Effective atomic number of central metal in the complexes

K_{2} [N i (C N)_{4}], [C u (N H_{3})_{4}] S O_{4}

and

K_{2} [P t C l_{6}]

are

x

y

and

z

respectively. Calculate the value of

\frac{x + y + z}{5}

The standard reduction potential value of three metallic cations X, Y and Z are 0.52, - 3.303 and – 1.18 V respectively. The order of reducing power of the corresponding metals is

M (C O)_{x} (N O)_{y} + N O - -- \to - C O M (N O)_{z}

Where

E A N

of metal

(M)

in both product and reactant is same and it is

54

. Then calculate value of

(x + y - z)

. (where

x, y

and

z

are natural numbers and

M

belong to

6^{t h}

group according to long form of periodic table).

Q. The standard reduction potential values of three metallic cations, X, Y and Z are 0.52, -3.03, and -1.18 V, respectively. The order of reducing power of the corresponding metal is

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EAN of central metal in the complexes K2[Ni(CN)4],[Cu(NH3)4]SO4 and K2(PtCl6) are x, y and z respectively. Calculate the value of x+y+z5.

Effective Atomic Number (EAN) = atomic no. - oxidiation state of central metal atom + 2 (no. of ligands) K2[Ni(CN)4]:EAN=28−2+2×4=34[Cu(NH3)4]SO4:EAN=29−2+2×4=35K2[PtCl6]:EAN=78−4+2×6=86x=34,y=35,z=86So,x+y+z5=34+35+865=31

EAN of central metal in the complexes $K_{2} [N i (C N)_{4}], [C u (N H_{3})_{4}] S O_{4}$ and $K_{2} (P t C l_{6})$ are x, y and z respectively. Calculate the value of $\frac{x + y + z}{5}$ .