EAN of Cr in - Cr NH 36- Cl 3 is-A- 35B- 32C- 33D- 34

The correct option is C 33Cr is in +3 oxidation state. EAN = Atomic number oxidation state + 2 × nbsp;Number of ligands = 24 nbsp;3 + 2 × nbsp;6 = 33 ...

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Standard X

Chemistry

Covalent Bond

EAN of Cr in ...

Question

EAN of $C r$ in $[C r (N H_{3})_{6}]$ $C l_{3}$ is:

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Solution

The correct option is B 33
$C r$ is in +3 oxidation state.
EAN = Atomic number - oxidation state + 2 $\times$ Number of ligands
= 24 - 3 + 2 $\times$ 6 = 33

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Similar questions

Q. The effective atomic number of Cr (atomic no. 24) in

[C r (N H_{3})_{6}] C l_{3}

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C r

[C r (N H_{3})_{6}]

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is:

EAN of Cr in $[C r (N H_{3})_{6}] C l_{3}$ is

The effective atomic number $(E A N)$ of $_{24} C r$ in $[C r (N H_{3})_{6}] C l_{3}$ is :

Q. The Oxidation no. of Cr in

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EAN of Cr in [Cr(NH3)6] Cl3 is:

The correct option is B 33Cr is in +3 oxidation state. EAN = Atomic number - oxidation state + 2 × Number of ligands = 24 - 3 + 2 × 6 = 33

EAN of $C r$ in $[C r (N H_{3})_{6}]$ $C l_{3}$ is:

The correct option is B 33
$C r$ is in +3 oxidation state.
EAN = Atomic number - oxidation state + 2 $\times$ Number of ligands
= 24 - 3 + 2 $\times$ 6 = 33