Earth revolves around sun in 365 days.Calculate its angular speed.

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Solution

$T = 365 d a y s = 365 \times 24 \times 3600 s$

$θ = 2 π$ for one revolution

$ω = \frac{θ}{T}$

$⟹ ω = \frac{2 π}{365 \times 24 \times 3600 s}$

$⟹ ω = 1.99 \times 10^{- 7} s^{- 1}$

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Earth revolves around sun in 365 days.Calculate its angular speed.

T=365days=365×24×3600sθ=2π for one revolutionω=θT⟹ω=2π365×24×3600s⟹ω=1.99×10−7s−1

$T = 365 d a y s = 365 \times 24 \times 3600 s$

$θ = 2 π$ for one revolution

$ω = \frac{θ}{T}$

$⟹ ω = \frac{2 π}{365 \times 24 \times 3600 s}$

$⟹ ω = 1.99 \times 10^{- 7} s^{- 1}$