E° for F2 + 2e- -> 2F- is 2.8V, E° for 1÷2 F2 + e -> F- is
Ans : 2.8V
Please give detailed explanation as I won't be able to understand concise answers .
Dear student,
If you think of the Nernst equation, you'll see that:
Since n corresponds to the number of electrons transferred, the ratio ΔG°/n remains constant, because any change in the stoichiometric coefficients will multiply both terms by the same value.
Therefore, we see that the potential is an intensive property, not depending on the dimensions of the system under study.
Thus electrode potentials are independent of the stoichiometry of the equation.